通过python 获取当前局域网内存在的IP和MAC

通过python 获取当前局域网内存在的ip

'''
通过ipconfig /all 命令获取局域网所在的网段
通过arp -d *命令清空当前所有的arp映射表
循环遍历当前网段所有可能的ip与其ping一遍建立arp映射表
for /L %i IN (1,1,254) DO ping -w 1 -n 1 192.168.3.%i
通过arp -a命令读取缓存的映射表获取所有与本机连接的设备的Mac地址。
'''
import os
import re
import time
from concurrent.futures import ThreadPoolExecutor, wait, ALL_COMPLETED
import psutil# 逻辑cpu个数
count = psutil.cpu_count()
print("cpu个数：",str(count))
import pandas as pd
def get_net_segment():with os.popen("arp -a") as res:for line in res:line = line.strip()if line.startswith("接口"):net_segment = re.findall("(\d+\.\d+\.\d+)\.\d+", line)[0]breakreturn net_segment
def ping_net_segment_all(net_segment):# for i in range(1, 255):#     os.system(f"ping -w 1 -n 1 {net_segment}.{i}")# 多线程并发 5个线程时耗时是30秒，8个线程是28秒with ThreadPoolExecutor(max_workers=4) as executor:for i in range(1, 255):executor.submit(os.popen, f"ping -w 1 -n 1 {net_segment}.{i}")
def get_arp_ip_mac():header = Nonelist1 = []#os.system('arp -a > temp11.txt')with os.popen("arp -a") as res:for line in res:line = line.strip()         if not line or line.startswith("接口"):continueif header is None:                header = re.split(" {2,}", line.strip())line1 = re.split(" {2,}", line.strip())list1.append(line1)df = pd.DataFrame(list1,columns=header)return df
def ping_ip_list(ips, max_workers=4):print("正在扫描在线列表")with ThreadPoolExecutor(max_workers=max_workers) as executor:future_tasks = []for ip in ips:future_tasks.append(executor.submit(os.popen, f"ping -w 1 -n 1 {ip}"))wait(future_tasks, return_when=ALL_COMPLETED)
if __name__ == '__main__':# 是否进行初始扫描init_search = True #Falseif init_search:print("正在扫描当前网段所有ip，预计耗时1分钟....")ping_net_segment_all(get_net_segment())last = Nonewhile 1:df = get_arp_ip_mac()df = df.loc[df.类型 == "动态", ["Internet 地址", "物理地址"]]if last is None:print("当前在线的设备：")print(df)else:online = df.loc[~df.物理地址.isin(last.物理地址)]if online.shape[0] > 0:print("新上线设备：")print(online)offline = last[~last.物理地址.isin(df.物理地址)]if offline.shape[0] > 0:print("刚下线设备：")print(offline)time.sleep(5)ping_ip_list(df["Internet 地址"].values)last = df