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问题：

将非负整数 num 转换为其对应的英文表示。示例 1：

输入：num = 123
输出："One Hundred Twenty Three"
示例 2：

输入：num = 12345
输出："Twelve Thousand Three Hundred Forty Five"
示例 3：

输入：num = 1234567
输出："One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
示例 4：

输入：num = 1234567891
输出："One Billion Two Hundred Thirty Four Million Five Hundred Sixty Seven Thousand Eight Hundred Ninety One"
提示：0 <= num <= 231 - 1

解答思路：

以下是使用 Java 语言实现将非负整数转换为英文表示的代码：

public class IntegerToEnglishWords {public static String numberToWords(int num) {if (num == 0) {return "Zero";}String[] belowTwenty = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};String[] tens = {"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};String[] thousands = {"", "Thousand", "Million", "Billion"};StringBuilder sb = new StringBuilder();int i = 0;while (num > 0) {if (num % 1000!= 0) {sb.insert(0, thousands[i] + " ");int hundred = num / 100;num %= 100;if (hundred > 0) {sb.insert(0, belowTwenty[hundred] + " Hundred ");}if (num > 0 && num < 20) {sb.insert(0, belowTwenty[num] + " ");} else if (num >= 20) {sb.insert(0, tens[num / 10] + " ");num %= 10;if (num > 0) {sb.insert(0, belowTwenty[num] + " ");}}}num /= 1000;i++;}return sb.toString().trim();}public static void main(String[] args) {int num = 1234567891;System.out.println(numberToWords(num));}
}

这个程序首先定义了一些数组，用于表示数字的英文单词。然后，它使用一个循环来处理数字的每三位，并将其转换为英文单词。在循环中，它根据数字的大小选择合适的单词，并将其添加到结果字符串中。最后，它返回结果字符串。
(文章为作者在学习java过程中的一些个人体会总结和借鉴，如有不当、错误的地方，请各位大佬批评指正，定当努力改正，如有侵权请联系作者删帖。)