LEEDCODE 220 存在重复元素3

class Solution {
public:int getId(int a, int valuediff){// 值// return a/(valuediff+1);return a < 0 ? (a ) -) / (valuediff + 1) - 1 : a / (valuediff + 1);}public: unordered_map<int, int> bucket;bool containsNearbyAlmostDuplicate(vector<int>& nums, int indexDiff, int valueDiff) {unordered_map<int, int> m;for(int i = 0; i < nums.size(); i++){int b = getId(nums[i], valueDiff);if(m.count(b))return true;else if(m.count(b-1) && abs(nums[i] - m[b-1])<=valueDiff){return true;}else if(m.count(b+1) && abs(nums[i] - m[b+1])<=valueDiff){return true;}m[b] = nums[i];if(i>=indexDiff)m.erase(getId(nums[i-indexDiff], valueDiff));}return false;}};

Thinking
1 位置 - 两层控制（只有这：m[b] = nums[i]; 控制位置。滑动窗口）

• 1）分桶
• 2） 分通后相邻部分的不确定用滑动窗口控制

2 值控制 if - else（都在控制值）