【水文】实现四则运算的简易计算器

代码：

#include <stdio.h>int main() {double num1, num2;char operator, ch;printf("请输入两个操作数和运算符（空格分隔）：");scanf("%lf %lf %c", &num1, &num2, &operator);switch (operator) {case '+':printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, num1 + num2);break;case '-':printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, num1 - num2);break;case '*':printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, num1 * num2);break;case '/':if (num2 != 0) {printf("%.2f %c %.2f = %.2f\n", num1, operator, num2, num1 / num2);} else {printf("除数不能为0\n");}break;default:printf("无效的运算符\n");break;}return 0;
}