Java 判断一个字符串在另一个字符串中出现的次数

1.split实现

package com.jiayou.peis.official.account.biz.utils;public class Test {public static void main(String[] args) {String k="0110110100100010101111100101011001101110111111000101101001100010101" +"01110110010101101010001111101011100100110101010010000011110100100100" +"01110111010011000000110100110110111001111111111001111001110010110110" +"10010101100111001101101110101011011010000011100000011110101111011001" +"11010010000000001000011001001001011100001111110110101100000001011101" ;int ct0=k.split("0000000000").length-1;int ct1=k.split("1111111111").length-1;System.out.println("0的数量："+ct0);System.out.println("1的数量："+ct1);}
}